web-php特性

url传入的数值都默认为字符串

web-89

重点在于绕过preg_match函数,且num是个int类型的数字

我们可以通过数组进行绕过,就得到了flag

php特性ctfshow

[HFCTF 2021 Final]easyflask

题目给了提示,有文件读取漏洞,读取源码

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#!/usr/bin/python3.6
import os
import pickle

from base64 import b64decode
from flask import Flask, request, render_template, session

app = Flask(__name__)
app.config["SECRET_KEY"] = "*******"

User = type('User', (object,), {
'uname': 'test',
'is_admin': 0,
'__repr__': lambda o: o.uname,
})


@app.route('/', methods=('GET',))
def index_handler():
if not session.get('u'):
u = pickle.dumps(User())
session['u'] = u
return "/file?file=index.js"


@app.route('/file', methods=('GET',))
def file_handler():
path = request.args.get('file')
path = os.path.join('static', path)
if not os.path.exists(path) or os.path.isdir(path) \
or '.py' in path or '.sh' in path or '..' in path or "flag" in path:
return 'disallowed'

with open(path, 'r') as fp:
content = fp.read()
return content


@app.route('/admin', methods=('GET',))
def admin_handler():
try:
u = session.get('u')
if isinstance(u, dict):#如果u对应的值是字典,会读取 u.b
u = b64decode(u.get('b'))
u = pickle.loads(u)#pickle反序列化
except Exception:
return 'uhh?'

if u.is_admin == 1:
return 'welcome, admin'
else:
return 'who are you?'


if __name__ == '__main__':
app.run('0.0.0.0', port=80, debug=False)

我们发现admin目录下面有反序列化函数,但我们不能直接访问

session伪造shell反弹

[watevrCTF-2019]Supercalc

打开页面,我们发现一个计算框

我们输入1+1,返回了2

image-20240926213408503

这种情况我们想到ssti模版注入

我们输入49

结果发生报错

session伪造